The sum of two numbers is 56, and their difference is 10. What are the numbers? ОА.
33 and 23
OB.
30 and 26
OC.
20 and 36
OD
20 and 30

Let the two numbers be 'm' and 'n'

Now we can get,

1) m + n = 56

2) m - n = 10

m + n = 56

n = 56 - m

m - n = 10

By substituting n = 56 - m we get,

m - (56 - m) = 10

56 - m - m = 10

56 - 2m = 10

-2m = 10 - 56

-2m = -46

m = - 46/-2

Now, we will find 'n' by the equation 1 ,

n = 56 - m

n = 56 - 23

33 + 23 = 56

33 - 23 = 10

Hence, verified