What is y=6x^2 +96x +388 in vertex form?
please show work

y = 6(x + 8)² + 4

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Using the method of completing the square.

y = 6x² + 96x + 388

The coefficient of the x² term must be 1, so

factor out 6 from 6x² + 96x

y = 6(x² + 16x ) + 388

To complete the square

add/subtract (half the coefficient of the x- term)² to x² + 16x

y = 6(x² + 2(8)x + 64 - 64) + 388

  = 6(x + 8)² - 384 + 388

y = 6(x + 8)² + 4 ← in vertex form

x> 6

step-by-step explanation:

8x+8> 7x+14

8x-7x> 14-8

x> 6

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1