Jaden and Dani are both travelling by train. Jaden's train travels 130 km in 75 minutes.
Dani's train travels 312 km.
It leaves at 15:15 and arrives at 18:30.
Work out the difference, in km/h, between the average speed of their trains.

 28.765957 km/hour

This value is approximate. Round it however you need to.

Explanation:

Let's convert 75 minutes to hours.

75 min = (75 min)*(1 hr/60 min) = (75/60) hr = 1.25 hr

So Jaden's train takes 1.25 hours to travel 130 km. Her train's speed is

speed = distance/time

speed = (130 km)/(1.25 hrs)

speed = (130/1.25) km per hour

speed = 104 km per hour

Let A = 104, so we can use it later.

Dani's train leaves at 15:15 and arrives at 18:30. We need to calculate the duration of elapsed time here.

Overall, the length of time from 15:15 to 18:30 is 0.75+2+0.5 = 3.25 hours.

Dani's train travels 312 km in 3.25 hours.

That train's speed is...

speed = distance/time

speed = (312 km)/(3.25 hours)

speed = (312/2.35) km per hour

speed = 132.765957 km per hour, approximately

Let B = 132.765957 so we can use it later.

Lastly, we subtract the values of A and B to get the final answer

C = difference in train speeds.

C = B - A

C = 132.765957 - 104

C = 28.765957 km/hour

This value is approximate. This says that Dani's train is approximately 28.765957 km/hour faster compared to Jaden's train.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

answer:

it is general formula that is used to write value to its excet position

a11 a12 a13

a21 a22 a23

it is the example of order 2 by 3 matrix in this

a11 means value occur in 1 st row 1st column

a12 means value occurs in 1st row 2nd column

a13 means value occur in 1st row and 3rd column

a21 means value occurs in 2nd row and 1st column

a22 means value occurs in 2nd row and in 2nd column

a23 means value occurs in 2nd row and in 3rd column