Write an equation for a line that passes through the points (2, 0) and (-4, -3).

(x1, x2) = (4,2)  

(y1, y2) = (0,12)

Use the slope fprmula to find the slope of the line.

m = (y2 - y1)/(x2 - x1)

m = (12 - 2)/(0 - 4) = 10/(-4) = -5/2

Then use the slope-intercept form to find the equation of the line.

y = mx + b

Use one of the above points ... I chose (0,12)

Substitute in x=0, y = 12, m = -5/2

12 = (-5/2)(0) + b

12 = 0 + b

12 = b

Now that we have "b" ... we substitute m and b into the slope intercept form to find our equation.

y = mx + b

The equation of the line is

y = (-5/2)x + 12

I hope it helps!

there is no graph so i cant sorry

step-by-step explanation: