What is the equation of the line that passes through the point (5,−2) and has a slope of -2/5

y + 2 = -2/5 (x - 5)

OR

y = (-2/5)x

Step-by-step explanation:

There are many ways you can find the equation.

There are two main ones, one called point-slope form, and the other called slope intercept form.

Point-slope form is easy. All you need a a point on the line, and the slope! Since they give you that in the question, all you need to do is plug things in.

Point slope form is y - = m(x - )

x and y are any points. and are the points that the problem gives you. m is the slope.

The equation would be y + 2 = -2/5 (x - 5).

Slope intercept form is a bit harder. You need a point and the y-intercept.

Since you already have the slope, all you need to find is the y-intercept.

Slope intercept form is y = mx + b

x and y are the given points. m is the slope, and b is the y-intercept.

The y intercept is when the x value of a point is 0.

To find b, you can plug in the information you have, which is the point and the slope.

y = mx + b

-2 = (-2/5)(5) +b

-2 = -2 +b

b = 0

Since b is 0, the equation would just be y = (-2/5)x.

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step-by-step explanation:

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