Find the constant of variation for the relation and use it to write an equation for the statement. Then solve the equation. If y varies directly as x, and y = 2 when x = 3, find y when x = 1.
a. y = 2x; y(1) = 2
c. 4
y - 3*; y(1) -
3
3
d.
y = -2
3
b.
yo 2 *;2(1) -
»-< x; 9(1) -
2
2.

the difference between a number and 5 is -2.

step-by-step explanation:

notice that the equation you are given has -2 (negative 2) on the right side, not 2. when you subtract 5 from a number n, you are finding the difference between the number and 5.

the difference between a number and 5 is -2.

idk

step-by-step explanation:

step-by-step explanation:

the true statements are:

r = set of real numbers

n = set of natural numbers, 1,2,

w = n u{0} = {0,1,}

27/4x^6 y^8

step-by-step explanation:

4(3x^2y^4)^3 (2x^3y^5)^4

=

108x^6 y^12 /16x^12 y^20

=

108 /16x^6 y^8

=

27 /4x^6 y^8