Explain what is meant by the equation lim f(x) = 5.
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f(x) = 5 for all values of x.
The values of f(x) can be made as close to 9 as we like by taking x sufficiently close to 5.
If [x1 - 91 < \x2 - 9), then |f(x1) - 51 < ]f(x2) – 5).
The values of f(x) can be made as close to 5 as we like by taking x sufficiently close to 9.
If |X1 - 91 < 1x2 - 91, then IF(x1) - 515 |F(x2) - 5).
Is it possible for this statement to be true and yet f(9) = 6? Explain.
Yes, the graph could have a hole at (9,5) and be defined such that f(9) = 6.
Yes, the graph could have a vertical asymptote at x = 9 and be defined such that f(9) = 6.
No, if f(9) = 6, then lim f(x) = 6.
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O No, if lim f(x) = 5, then f(9) = 5.
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