A scientist studying water quality measures the lead level in parts per billion (ppb) at each of 49 randomly chosen locations along a water line. Suppose that the lead levels across all the locations on this line are strongly skewed to the right with a mean of ppb17 and a standard deviation of 14ppb. Assume that the measurements in the sample are independent. Required:
What is the probability that the mean lead level from the sample of 49 measurements T is less than 15 ppb?

The probability that the mean lead level from the sample of 49 measurements T is less than 15 ppb

P(x⁻< 15) = 0.1587

Step-by-step explanation:

Step(i):-

Given that the size of the sample 'n' =49

Mean of the Population = 17ppb

The standard deviation of the population = 14ppb

Let 'X' be the random variable in a normal distribution

Step(ii):-

The probability that the mean lead level from the sample of 49 measurements T is less than 15 ppb

P(x⁻< 15) = P(Z<-1) = 1-P(Z>-1)

                             = 1-(0.5+A(-1))

                             = 0.5 - A(1)

                            = 0.5-0.3413

                            = 0.1587

Final -

The probability that the mean lead level from the sample of 49 measurements T is less than 15 ppb

P(x⁻< 15) = 0.1587

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step-by-step explanatio89

you could deduce the conclusion directly using the facts pertaining to the specific situation.

hope this .