What is an equation of a line, in point-slope form, that passes through (1, −7) and has a slope of −2/3 ?

a. y+7=−23(x−1)y+7=−23(x−1)

b. y−7=23(x−1)y−7=23(x−1)

c. y−7=−23(x+1)y−7=−23(x+1)

d. y+7=23(x+1)y+7=23(x+1)

- A.

Explanation:-

We know that the equation of a line passing through point (a,b) whose slope is m, is

Thus, the equation of a line passing through point (1, −7) whose slope is ,

∴ A. is the right answer. The equation of a line passing through point (1, −7) whose slope is .

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

it would be 6xy and -16xy.