Juan and Ari went to the farmers market to buy fruit. Juan's bag of apples that he bought weighed StartFraction 31 over 7 EndFraction pounds. Ari's bag of oranges that he bought weighed StartFraction 19 over 3 EndFraction pounds. Using compatible fractions, estimate how much heavier Ari's bag is compared to Juan's bag. 1 and one-half pounds 2 pounds 6 pounds 10 and one-half pounds

Juan and Ari went to the farmers market to buy fruit. Juan’s bag of apples that he bought weighed 31/7 pounds. Ari’s bag of oranges that she bought weighed 19/3 pounds. Using compatible fractions, estimate how much heavier Ari's bag is compared to Juan's bag.

A) 1 and one-half pounds

B) 2 pounds

C) 6 pounds

D) 10 and one-half pounds

B: approximately 2 pounds

Step-by-step explanation:

Juan’s bag weighed 31/7 pounds

Ari's bag weighed 19/3 pounds.

We are told to use compatible fractions to determine the difference. Thus we have to make sure the denominator is the same;

For Juan, let's multiply both numerator and denominator by 3 to get; 93/21 pounds

For Ari, let's multiply both numerator and denominator by 7 to get; 133/21

Thus, difference is;

(133/21) - (93/21) = 40/21

This gives;

1.9 pounds heavier

This is approximately 2 pounds

cosine

step-by-step explanation:

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)