Jenny goes to the shop she buys . three cups for £1.24 each
.three saucers for 95p each
. a teapot for £6.18
jenny has £20 to spend she also wants to but some plates, which are £1.57 each.
what is the greatest number of plates jenny she can buy

5

Step-by-step explanation:

1.24 times 3 = 3.72

.95 (the value of pence to a pound in decimal form) = 2.85

6.18 for the teapot

2.72+2.85+6.18=11.75

She now has £8.25 left (20-11.75).

8.25/1.57=the amount of plates she can buy: 5.25477707006, so 5 with some money left

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!