edbgsbsuisbui isae uasd 7sashad uygasjdga asdiasHDYUAS GDIUASGYASGDUIASG UDYSAIDUGAsd Apilsayfduaas7 basda gdusagdjsagfiua faBFGAUFGAF VAFJSAFJAIJFSAJ FASJFSAHFSAJFJSA FUSAF AFS jfah asfhfasfihashfiaisfhksh hsihfsai fsahjfh /.uys syayyysvsg adchshdgjfsjfsi fsfjssjaija AJUASHSHAJ J JFASIJFSAOF AOISYF AFAOPSF AOSUIFAF UAIFU AFSOFASUF ;HSh

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!

y + 11 = (1/4)(x + 16)

step-by-step explanation:

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: