A barracuda swam directly toward a coral reef at a constant velocity for 8seconds. In one-quarter of that time, the barracuda swam 14meters. What was the barracuda's velocity?

i think it would be 42cm

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

4+4+2x

or

2x+8

step-by-step explanation: