What is the polar form of -9-9i√3?

18(cos(4pi/3) + i sin(4pi/3))

Step-by-step explanation:

step 1: find the modulus (|z|=√(a^2 + b^2)

|z|=√((-9)^2+(-9√3)^2)= 81+243= 324 => √324=18

step 2: find the argument using theta =tan^-1 (y/x)

theta=tan^-1((-9√3)/-9) = √3

the tangent value of √3 in the third quadrant has the degree measure of 240 and the radian measure of 4pi/3.

Now put them together!

1. d.90

2. e. none of these (80)

3. a. 0

4. b. 6

5. e. none of these (10)

6. a. 5

unless if u could do my questions, if not i wouldn't want to