[Function Composition] could someone help me with this answers or show work either is fine

6n - 14

Step-by-step explanation:

Given;

g(n) = 3n+1 and f(n) = 2n-5

We are to find (gof)(n)

(gof)(n) = g(f(n))

g(f(n)) = g(2n-5)

Replace n with 2n-5 in g(n)

g(2n-5) = 3(2n-5) + 1

g(2n-5) = 6n - 15 + 1

g(2n-5) = 6n - 14

Hence (gof)(n) is 6n - 14

the answer to this question is in the pic

a

step-by-step explanation:

the answer is a