In each of the months June, July, and August, the number of accidents occurring in that month is modeled by a Poisson random variable with mean 1. In each of the other 9 months of the year, the number of accidents occurring is modeled by a Poisson random variable with mean 0.5. Assume that these 12 random variables are mutually independent. Calculate the probability that exactly two accidents occur in July through Novembe

Step-by-step explanation:

From the question we are told that

Sample size n=3

Sample mean 1  

Sample mean 2

Generally the Probability that 2 accidents occurs from July to August is mathematically given by

Generally the probability that 2 deaths occurs from September through November is mathematically given by

Therefore

Total Mean accidents

Generally the probability of  two accident per month is mathematically given by

Therefore the probability of having  2 accidents from July through to November is

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.