Two of the tangents to a circle meet at Q, which is 25 cm from the center. The circle has a 7-cm radius. To the nearest tenth of a degree, find the angle formed at Q by the tangents.

31.3

Step-by-step explanation:

Calculation to find the angle formed at Q by the tangents

First step is to use the tangent of the angle to calculate half the angle (A) at Q

Tan(A) =7-cm radius/25 cm

Tan A = 15.64

Since since we were told that two of the tangents to a circle meet at Q, Now let calculate the angle formed at Q by the tangents

Angle at Q(Tangents)=2*15.64

Angle at Q(aTangents)= 31.3

Therefore the angle formed at Q by the tangents will be 31.3

d

step-by-step explanation:

by observation, we can see that the the graph is simply the graph of y = |x| that has been shifted 4 units downwards and 3 units to the left.

we can recognize in choice d :

y = | x + 3 |   - 4 (rewriting in general form)

y = | x - (- 3) |   - 4

the "-4 " term means   that the graph has been shifted by 4 units in the negative y direction

the "-3 " term means   that the graph has been shifted by 3 units in the negative x direction

this matches our observation of the graph described above.

you should at least use a calculater

step-by-step explanation: