Question 3: 20 pts The pressure P exerted by a force varies inversely as the area A on which the force is applied. If 16 N/At of

pressure is exerted by a force on an area of 3 it?, what is the pressure exerted by the same force on an area of

6 ft22

the pressure exerted by the same force on an area of of 6 ft² is 8 N/ft²

Step-by-step explanation:

Given that;

pressure and area are inversely proportional to each other.

i.e  P ∝ 1/A

so

P₁A₁ = constant

i.e P₁A₁ = P₂A₂

In the question;  P₁ = 16 N/ft² and  A₁ = 3 ft² while P₂ is unknown and A₂ = 6ft²

so w substitute

16 × 3 = P₂ × 6

48 = 6P₂

P₂ = 48 / 6

P₂ = 8 N/ft²

Therefore, the pressure exerted by the same force on an area of of 6 ft² is 8 N/ft²

the correct answer is 828.07

0.6, 3/5, and 6% are the 3 same portion.

but, when they're all changed to a decimal they would equal to 0.6.

hope this , good luck!