The following function 1/3x^3 - 2x^2 - 3x + 4 is defined in the interval (-4, 4). 1) Find it's relative maxima value. Options:
a) x= 1
b) x= 0
c) x= 3
d) x=2

2) Find it's relative minima value. Options:
a) x= 5
b) x= 3
c) x= 1
d) x= 0

3) Find it's absolute maxima. Options:
a) x= 1
b) x= 0
c) x= 4
d) x= -4

4) Find it's absolute minima. Options:
a) x= 3
b) x= -4
c) x= 1
d) x= 0

5) Find the y-intercept/ where the curve crosses the y-axis. Options:
a) y=0
b) y= 3
c) y= -4
d) y= 4

B) Find the derivative of the function (x^2 + 4x) ÷ (x+1)
Options:
a) (3x^2 + 10x + 4) ÷ (x + 1)
b) (3x^2 + 2x + 4) ÷ (x+1)^2
c) (x^2 + 2x + 4) ÷ (x + 1) ^2
d) x^2 + 2x + 4

The equation P= 30(1.03)^t, where t stands for the number of years AFTER 1980. While P stands for the population of a country in millions.

a) In what year will the population double?
i) 1974 ii) 2004 iii) 2005 iv) 1990

b) In what year was the population 25 million?
I) 1972 ii) 1975 iii) 1973 iv) 1974

c) What was the population in 1980?
i) 24.5 million ii) 32 million iii) 31 million iv) 19 million

d) In what year will the population be 50 million?
i) 1997 ii) 1998 iii) 2000 iv) 2004

It's not compulsory for a single person to answer all the questions. Answer the ones you know. But if you know the answers to all the questions please do share. I will appreciate very much speedy responses. I have a maths exam tomorrow and I need help with such questions. Thank you so very much