Mathematics, 19.01.2021 19:10, devin3634

Prove: An odd number cubed is an odd number.
n +
(2n + 1)3 = [ 2 ]n3 + [ ]n2 + [
[](4n3 + 6n2 + 3n) +
= an odd

Answers: 2

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Prove: An odd number cubed is an odd number.
n +
(2n + 1)3 = [ 2 ]n3 + [ ]n2 + [
...