A family has two cars. The first car has a fuel efficiency of 20 miles per gallon of gas and the second has a fuel efficiency of 15 miles per gallon of gas. During one particular week, the two cars went a combined total of 1325 miles, for a total gas consumption of 75 gallons. How many gallons were consumed by each of
the two cars that week?

40 and 35

Step-by-step explanation:

If we say the first car uses x gallons then the second car must use 75 - x gallons.

The distance travelled is the number of gallons used * the efficiency of the car.

20x + 15(75-x)=1325

20x + 1125 - 15x = 1325

5x = 200

x = 40

This means that the first car uses 40 gallons and the second car uses 75-40= 35 gallons

(sin 42)/31. = sinx)/37

sinx = 37 (sin42)/31

= 37× 0.66/31 = 0.787

x= 51.9

other angle opposite to y = 180-51.9-42

= 180- 93.9 =86.1

so

sin42)/31 = sin 86.1)/y

0.021 = 0.997 /y

y= 0.997/0.021 =47.47

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation: