The function f(x) = x^3 has been transformed, resulting in function h. h(x) = -(x+2)^3-4

To create function h, function f was translated 2 units (down, to the left, up to the right) , translated 4 units (to the right, down to the left, up) , and reflected across the (y-axis, x-axis) .

To create function h, function f was translated 2 units to the right, translated 4 units down and reflected across the y-axis.

Step-by-step explanation:

Since f(x) = x^3 is transformed to h(x) = -(x+2)^3-4, by

1. Adding 2 to x in x³ to give f'(x) = f(x + 2) = (x + 2)³.

2. We now translate f(x + 2) down by subtracting 4 from f(x + 2) to give

f''(x) = f'(x) - 4 = f(x +2) - 4 = (x + 2)³ - 4.

3. We now reflect f'(x) across the y-axis by multiplying (x + 2)³ by -1 to get

h(x) = -(x + 2)³ - 4.

its 2 to the left, 4 units down, and over the x axis.

Step-by-step explanation:

not my answer just the one from the comments

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0