Harry has a batting average of .200 (i. e., a 20 percent chance of a hit each time he's at bat). Scouts for a rival baseball club secretly observe Harry's performance in 12 random times at bat. What is the probability that Harry will not get more than 2 hits

0.9999

Step-by-step explanation:

Probability of a bit whenever he is at bat = 0.20

Probability when not having a hit = 1-0.20

= 0.80

n = 12

P = 0.80

We have a binomial distribution

P(X=x) = nCx*P^x(1-p)^n-x

P(x>2) = 1-p(x<=2)

= 1-[(12C0 * 0.8⁰*(1-0.8)¹²) +(12C1 * 0.8¹ * (1-0.8)¹¹) + (12C2 * 0.8² * (1-0.8)¹⁰)]

= 1-(0.000000004096+0.000000196608+0.000004325376)

= 1-0.00000452608

This is approximately

0.9999

connie < felicia < stew

step-by-step explanation:

stew:

we need to find the slope

m = (y2-y1)/ (x2-x1)

    = (2650-795)/(10-3)

    = 1855/7

265 words per minute

connie:

we need to find the slope

m = (y2-y1)/ (x2-x1)

we have two points (0,0) and (4,800)

m = (800-0)/(4-0)

  m = 800/4

    200 words per minute

felicia:

260 words per minute

200< 260 < 265

connie < felicia < stew

-6 is the correct option from the above given options