Let A be a 3 X 4 matrix. If b = a1 + a2 + a3 + a4
then what can you conclude about the number of solutions of the linear system Ax=b?
Explain.

Let A be a 3 X 4 matrix. If

b = a1 + a2 + a3 + a4

then what can you conclude about the number of solutions of the linear system Ax=b?

Explain.

The system has infinitely many solutions

Step-by-step explanation:

Since b= a1 + a2 + a3+ a4 if it follows that x= (1,1,1,1)^T is a solution to the equation Ax = b.

Since the matrix contains 3 rows there can be 3 nonzero rows and consequently

3 lead variables at most after we compute the row echelon form of the matrix

At least of the variables is free variables is free variable.

The system has infinitely many solutions

50x5=$250

step-by-step explanation:

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!