The diagram shows information about the final 70 seconds of a car journey. (a) Find the deceleration of the car between 60 and 70 seconds.

I have attached an image showing the diagram.

-2 m/s²

Step-by-step explanation:

From the diagram, in decelerating from between 60 to 70 seconds, it moved from a velocity of 20 m/s to 0 m/s.

Thus, using Newton's first equation of motion, we can find the deceleration;

a = (v - u)/t

Time (t) = 70 - 60 = 10 s

Final velocity (v) = 0 m/s

Initial velocity (u) = 20 m/s

Thus;

a = (0 - 20)/10

a = -20/10

a = -2 m/s²

d

step-by-step explanation:

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!