Write the equation of a line parallel to the line y = 2x that passes through 0,4

Note: this answer assumes that the question accepts the equation to be written in slope-intercept form.

y = 2x + 4

Step-by-step explanation:

To write an equation of a line knowing a slope and a y-intercept, you can use slope-intercept form, or y = mx+ b.

1) Lines that are parallel to each other have the same slope. The answer needs to be parallel to the line y = 2x, so whatever the slope of that equation is must be the slope of the answer, too.

y is isolated in y = 2x, meaning it is in slope-intercept form, or y = mx +b form. The m in y = mx + b represents the slope of the line. In the equation y = 2x, the 2 is in the place of that m - meaning that 2 is the slope of that line, and therefore the slope of the answer, too.

2) The question also says that (0,4) is a point the line must pass through as well. However, notice that the x-value of the point is 0, meaning it is positioned on the y-intercept. Therefore, (0,4) must be the y-intercept of the equation.

3) To write a linear equation with y = mx + b form, you need to replace the m and the b for real values. The slope is 2, and m represents the slope - so write 2 in place of the m. The b represents the y-value of the y-intercept point - knowing that point is (0,4), write 4 in place of the b. Therefore, the answer would be y = 2x + 4 (assuming the question can be written in slope-intercept form).

idk

step-by-step explanation:

i don't know

a is the correct