Evelyn is working two summer jobs, making $18 per hour lifeguarding and making $11 per hour tutoring. In a given week, she can work a maximum of 15 total hours and must earn no less than $200. If Evelyn worked 8 hours lifeguarding, determine the maximum number of whole hours tutoring that she can work and still meet her requirements. If there are no possible solutions, submit an empty answer.

Evelyn can work a maximum of hours tutoring.

Step-by-step explanation:

Evelyn earns per hour lifeguarding and she worked hours lifeguarding.

So, total money earned by lifeguarding .

She must earn no less than .

So, money left to earn .

Evelyn worked hours lifeguarding. She can work a maximum of total hours. So, she can work hours.

Evelyn earns per hour tutoring.

So, total money earned by tutoring .

Therefore, the total money earned .

Hence, Evelyn can work a maximum of hours tutoring.

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation:

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204