The shadow of a 60 foot pole is a 100 feet long. What is the angle of evaluation from the end of the shadow to the top of the pole?

The angle is approximately .

Step-by-step explanation:

The description i the given question can be represented with the sides of a right angled triangle.

Applying the appropriate trigonometric function, we have;

Tan θ =

In the question, opposite side = 60 feet, and adjacent side = 100 feet.

Tan θ =

         = 0.6

θ = 0.6

  =

θ =

The angle of elevation from the end of the shadow to the top of the pole is .

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.