Pls help⚠️ The perimeter of a rectangle is 560 feet. Let X represent the width of the rectangle. Write a quadratic function for the area A of the rectangle in terms of its width.

9514 1404 393

  A(x) = x(280 -x)

Step-by-step explanation:

The perimeter is given by the formula ...

  P = 2(L +W)

Using the given values, we can solve for the length of the rectangle:

  560 = 2(L +x)

  280 = L +x

  280 -x = L

The area is the product of length and width, so the area is ...

  A = LW

  A(x) = (280 -x)x

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

b

step-by-step explanation: