3. North
AL1400
o
450 m
400 m
350 m
180
-140=40
The diagram shows a field ABCD.
The bearing of B from A is 140°.
C is due east of B and D is due north of C.
AB = 400 m, BC = 350 m and CD = 450 m.
(a) Find the bearing of D from B.

Best answer that i found on yahoo ok   set :   x= length of 2nd piece in cm  x- 3= length of 1st piece in cm  x-4= length of 3rd piece in cm  then since you know they all came from the 20 cm ribbon you add them together and set them equal to 20x+ x-3 +x-4 = 20  3x - 7= 20  3x= 27  x= 9  the shortest piece is the third piece which is x- 4  x-4  9-4 = 5  the length of the smallest piece is 5 cm.  the other lengths are  9 cm  6 cm

The answer should be 5.