The perimeter of parallelogram ABCD is 92 cm. AD is 1 cm more than twice AB. Find the lengths of all four sides of ABCD (1 point)

Step-by-step explanation:

The perimeter of a parallelogram ABCD IS 92cm. AD is 1cm more than twice AB. Find the lengths of all four sides of ABCD

Let x = |AD|   (the length of the side AD).

Let y = |AB|   (the length of the adjacent side AB).

Then

2x + 2y = 92   (the perimeter)

x - 2y = 1    ("AD is 1cm more than twice AB.")

Add the two equations (both sides) and get

3x = 92 + 1  --->  3x = 93  --->  x = 93/3--->  x = 31.

Then from the second equation  2y = x - 1 = 30-1 = 30.

Hence, y = 30/2 = 15.

Answer. The sides of the parallelogram are 31, 15, 31 and 15 cm long.

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: