If the distance from the center of a Ferris wheel to one of the seats is approximately 90 feet what is the distance traveled by a seated person, to the nearest foot, in four revolutions r=90 feet

2261.9 ft

Step-by-step explanation: One trip around is one circumference of a circle. The circumference is 2πr. That's 2(π)(90 ft) = 565.4867 ft. Multiply by 4 trips around for a total distance of 2261.9 ft If you care about significant figures, then you only have report  sig fig, so that's 2000 ft.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

22

step-by-step explanation: