Which table of ordered pairs represents a proportional relationship? A 2-column table with 3 rows. Column 1 is labeled x with entries negative 3, negative 4, negative 5. Column 2 is labeled y with entries 3, 2, 1.
A 2-column table with 3 rows. Column 1 is labeled x with entries negative 1, negative 3, negative 5. Column 2 is labeled y with entries 1, 3, 5.
A 2-column table with 3 rows. Column 1 is labeled x with entries negative 2, negative 4, negative 6. Column 2 is labeled y with entries negative 5, negative 7, negative 9.
A 2-column table with 3 rows. Column 1 is labeled x with entries negative 2, negative 3, negative 4. Column 2 is labeled y with entries 0, negative 1, negative 2.

answer: c. is your answer

step-by-step explanation: get me a black leather coat

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)

answer:   x*94 +688*6   = 267*100

94x+4128=26700    

94x=22572     /94

x=240.128

step-by-step explanation: mark as brainlest reallly need it thx