At time t = 0 you have 100 grams of radioactive chromium-48. ten hours later you have 74 grams left. what is the half life of chromium-48?

To calculate what is asked we use the formula for radioactive decay. It is expressed as follows:

An = Ao (e^(-kt))

We calculate as follows:

An = Ao (e^(-kt))
74 = 100 (e^(-k(10)))
k = 0.0301

1/2 = (e^(-0.0301t))
t = 23 hours

Hope this answers the question.