According to a recent survey, 47 percent of the people living in a certain region carry a certain genetic trait. People from the region will be selected at random one at a time until someone is found who carries
the genetic trait. Let the random variable X represent the number of people selected to find one person
who carries the genetic trait. How many people from the region can we expect to be selected to find one
person who carries the genetic trait?

2.13

Step-by-step explanation:

.47 would be your probability of randomly selecting but your'e solving geometrically so think how many trials until successful.

use u x(mean)= 1/.47 to get around 2.13

since your problem is x^4 = 81, what you have to undeo is the "to the fourth power" part.

the inverse (opposite operation) of "to the fourth power" is "to the fourth root".

  (x^4) ^ ¼   = 81 ^ ¼  

  81 = 3^4     so (3 ^ 4) ^ ¼   =   3 ^ 1   = 3

by hand: (3 ^ 4) ^ ¼   =   3 ^ (4 x ¼) = 3 ^ 1   = 3   (when you take a power to a power, multiply the exponents.)

or, do it by calculator. one way of finding the fourth root is to use ^ (1/4)

step-by-step explanation:

can you rephrase the question ? it is unclear : -)

step-by-step explanation: