delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.
she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.
let 'p' represent the number of pounds of peanuts needed to make the new mixture, and
let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.
:
p + m = 5
therefore
m = (5-p)
write an equation based on the percent of peanuts
1p + .2m = .6(5)
replace m with (5-p)
p + .2(5-p) = .6(5)
p + 1 - .2p = 3
p - .2p = 3 - 1
.8p = 2
p = 2/.8
p = 2.5 lbs of peanuts required
then
5 - 2.5 = 2.5 lbs of the peanut/almond mixture required
:
a) what is the system that models this situation?
p + m = 5
1p + .2m = .6(5)
