Calculate the area of trapezium CDEF:) In the diagram shown
. CDEF is a trapezium
.ABCF is a rectangle
. BD = 9cm
.AB = 6cm
.EF = 3cm
Perimeter of ABCF = 20cm

6+6=12

20-12 = 8

8/2 = 4

BC = 4 cm

9 - 4 = 5

CD = 5

5 + 3 = 8

8/2 = 4

4 X 6 = 24

answer: x

step-by-step explanation:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.