![\sf 3a^2-24ab+48b^2\\\\Taking \ 3 \ as \ common\\\\= 3 (a^2-8ab+16b^2)\\\\= 3 [(a)^2 - 2 (a)(4) + (4b)^2]\\\\Using \ Formula \ a^2 - 2ab + b^2 = (a-b)^2\\\\= 3 (a-4b)^2\\\\= 3 (a-4b)(a-4b)\\\\\rule[225]{225}{2}](/tpl/images/1035/1276/77134.png)
Please help this is my last question
Please don't put a random answer just for points
zo...
Mathematics, 14.01.2021 09:30, daustin57
Please help this is my last question
Please don't put a random answer just for points
zoom in to see picture clearer ty^^
Answers: 1
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