What’s the equation in point slope form of the line that passes through the point (-1,1) and has a slope of 4 ?

9514 1404 393

  y -1 = 4(x +1)

Step-by-step explanation:

The point-slope form of the equation of a line with slope m through point (h, k) is ...

  y -k = m(x -h)

For m=4 and (h, k) =(-1, 1), the equation is ...

  y -1 = 4(x +1)

168

step-by-step explanation:

i am pretty sure that the answer is 168

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form