Which equation will solve the following word problem? One small pitcher and one large pitcher can hold 12 cups of water. If the large pitcher is twice the size of the small pitcher, how much does the small pitcher hold? S = 12/2S

2S = 12/S

2S + S = 12

2S - S = 12

Option 3
Amount of water hold by both the pitchers (Large + small) = 12 cups
Let the small pitcher holds the water = S cups
If the water hold by the large pitcher is twice the size of the small pitcher, then the amount of water hold by large pitcher = 2S
Total amount water hold by both = S + 2S
Equation for this situation will be,
S + 2S = 12
Therefore, Option (3) will be the answer.