A logarithmic function of base ‘3’ has a vertical asymptote at the line x=1. Its graph contains the point (2,1). What is the equation of the function? 1) f(x)=log3 (x+1)
2) f(x)=log3(x-1)+1
3) f(x)=log3(x+1)+1
4) f(x)=log3(x)+1

9514 1404 393

  2)  f(x) = log3(x -1) +1

Step-by-step explanation:

The vertical asymptote of the log function is normally x=0. In this function, it is moved to the right 1 unit. That is accomplished by replacing the function argument x with (x-1). Only one answer choice matches:

  f(x) = log3(x -1) +1

the answer would be 150 books

step-by-step explanation:

if you divide 300 by 2 you will get 150

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)