PLEASE HELP PLEAS Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 5−x and y = 2x + 1 intersect are the solutions of the equation 5−x = 2x + 1.
Part B: Make tables to find the solution to 5−x = 2x + 1. Take the integer values of x between −3 and 3.
Part C: How can you solve the equation 5−x = 2x + 1 grap hically?

y = 5 - x → standard form y = -x + 5

y = 2x + 1

A: If two sides of an equation are set equal to each other, their value is a point of intersection because they will both equal a certain value.

B:

3 → 5 - 3 = 2(3) + 1 → 2 = 6 + 1 → 2 ≠ 7

2 → 5 - 2 = 2(2) + 1 → 3 = 4 + 1 → 3 ≠ 5

1 → 5 - 1 = 2(1) + 1 → 4 = 2 + 1 → 4 ≠ 3

0 → 5 - 0 = 2(0) + 1 → 5 = 0 + 1 → 5 ≠ 1

-1 → 5 - (-1) = 2(-1) + 1 → 6 = -2 + 1 → 6 ≠ -1

-2 → 5 - (-2) = 2(-2) + 1 → 7 = -4 + 1 → 7 ≠ -3

-3 → 5 - (-3) = 2(-3) + 1 → 8 = -6 + 1 → 8 ≠ -5

algebraically ↓

-x + 5 = 2x + 1 → 4 = 3x → x = 4/3

C: graphically

graph both equations and find point of intersection

We know these points are the solutions to because by setting the two equations equal to each other, we find where they intersect, and those points are the solutions to the equation.

Since none of those values are correct solutions, let's solve this equation algebraically, even though the question doesn't ask for us to do so.

We can solve the equation graphically by graphing both and , then finding where they meet. This is shown in the attachment below.