What theorem shows that ΔACE ≅ ΔBCD? There are two triangles, triangle ACE and triangle BCD with common vertex C. The angle ACE and angle BCD are opposite angles. Side AC is congruent to side BC. Side EC is congruent to side

A. HL
B. AAS
C. ASA
D. SAS

step-by-step explanation:

i think you should think about the question and not look online.

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles

h/o/e/s mad

step-by-step explanation:

si si si