Write down three integers, all less than 25,whose range is 8 and mean is 11.

let

x> the first integer

y> the second integer

z> the third integer

x < y < z < 25

we know that

Median=13

Median=(x+y+z)/3

13=(x+y+z)/3

x+y+z=39> equation 1

range=10

The range is the difference between the largest number within the set and the smallest number in the set

so

range=z-x

z-x=10> z=x+10> equation 2

to find the solution we will assume different values of x (See the attached table)    

terms

x < y < z < 25

z=x+10

y=39-z-x

The solution can be

7,15,17

8,13,18

9,11,19    

throw the computer

step-by-step explanation: