The angle bisectors of AABC are AV, BV, and CV. They meet at a single point V. (In other words, V is the incenter of AABC.)
Suppose TV=18, CV=27, mZTCU=22°, and m2 SAV=32°.
Find the following measures.
Note that the figure is not drawn to scale.
B
mZSAU = 1
T
S
m 2 SBV =
V
SV = 0
А
U
Check

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