Suppose you want to investigate the proportion of women police officers. How large should a sample be if the margin of error is .05 for a 92% confidence interval

A sample of 307 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

The margin of error is of:

In this question, we have that:

We dont know the true proportion of women police officers, so we use , which is when the largest sample size would be needed.

92% confidence level

So , z is the value of Z that has a pvalue of , so .

How large should a sample be if the margin of error is .05 for a 92% confidence interval

We need a sample of n, and n is found when . So

Rounding up

A sample of 307 is needed.

the answer is. -82562234434584

step-by-step explanation:

c: y > - 1/6x + 1

step-by-step explanation:

dashed line - meaning this < or > also not equal

solid line - meaning this < or > also equal

your answer is c because y > means up & it's shaded up, but y < means down

hope this ! : )