Harold is buying packages of corndogs and hamburgers for a cookout. Harold bought 5 more packages of hamburgers than corndogs. A package of corndogs costs $2.00 and a package of hamburgers costs $5.00. Harold spent a total of $95.00. Write two equations. How many packages of hamburgers did Harold buy? How many packages of corndogs did Harold buy?

Number of packages of hamburgers bought = 15

Number of packages of corndogs bought = 10

Step-by-step explanation:

Cost of a package of corndogs = $2.00

Cost of a package of hamburgers = $5.00

Let number of packages of corndogs bought =

Let number of packages of hamburgers bought =

Number of packages of hamburgers bought are 5 more than the cordogs.

The first equation can be written as:

Total money spent = $95.00

Money spent on corndogs = Price of one package of corndogs Number of packages of corndogs bought = $2

Money spent on hamburgers = Price of one package of hamburgers Number of packages of hamburgers bought = $5

As per question statement, the second equation can be written as:

Putting the value from equation (1) to equation (2):

Putting this value in the equation (1):

Number of packages of hamburgers bought = 15

Number of packages of corndogs bought = 10

answer: options?

step-by-step explanation:

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".