Point S is on line segment \overline{RT} RT . Given RT=x+5,RT=x+5, ST=4x-9,ST=4x−9, and RS=x-2,RS=x−2, determine the numerical length of \overline{RT}. RT .

9 units

Step-by-step explanation:

If point S is on the line RT, then RS + ST = RT

Given

RT=x+5

ST=4x−9

RS=x-2

Substitute into the formula

x-2+4x-9 = x + 5

Collect like terms

x+4x-2-9 = x+5

5x - 11 = x + 5

5x - x = 5+11

4x = 16

x = 4

Get RT

RT = x+5

RT = 4 + 5

RT = 9 units

Hence the length of RT is 9 units

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

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step-by-step explanation: vsfdvsfvd