Solve 3(z+1) + 11 < -2(z+13)

The answer is z < -8. First of all, you use distributive property to get rid of the brackets. 3(z) = 3z and 3(1) = 3. The left side of the equation is now 3z + 3 + 11. Then, on the other side, -2(z) = -2z and -2(13) = -26. The right side of the equation is now -2z - 26. Then we combine like terms on the left side so we end up with 3z + 14 while the other side is still -2z - 26. We can put all of the z on the left side, so add 2z to both sides and then we have 5z + 14 < -26. We can put all of the “regular” numbers on the right side, so subtract 14 from each side and then we have 5z < -40. Divide each side by 5 and you end up with z < -8!

Step-by-step explanation:

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step-by-step explanation: