Which function is shown in the graph below? On a coordinate plane, a function is shown. The curve starts in quadrant 4 and curves up to quadrant 1. It goes through (0.5, negative 0.4), (1, 0), and (6, 1).
y = log Subscript one-sixth Baseline x
y = log Subscript 0.5 Baseline x
y = log Subscript 1 Baseline x
y = log Subscript 6 Baseline x

irrational, cannot

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

hi im bob : l

step-by-step explanation: